Question

Trigonometry Question

Answer 1

I attached the ques.

Answer 2

@One098 @k_lynn @Night-Watcher @Goku-Kai @ilovewolf @Mesopretty @sammixboo @uChezzy @I_Always_Smiling @AuroraB @skullpatrol

Answer 3

I'm not that advanced, sorry.

Answer 4

@One098 its okay

Answer 5

@One098 @k_lynn @Night-Watcher @Goku-Kai @ilovewolf @Mesopretty @sammixboo @uChezzy @I_Always_Smiling @AuroraB @skullpatrol

Answer 6

Please see the attachment vj.jpg

Answer 7

@ganeshie8 @aaronq @dan815 @iGreen @sammixboo

Answer 8

\(\large \begin{align} \color{black}{\sin^2x+\sin^2y+\sin^2z=0 \hspace{.33em}\\~\\
\sin^2x+\sin^2y+\sin^2z+(\cos^2x+\cos^2y+\cos^2z) \hspace{.33em}\\~\\
=(\cos^2x+\cos^2y+\cos^2z) \hspace{.33em}\\~\\
(\sin^2x+\cos^2x)+(\sin^2y+\cos^2y)+(\sin^2z+\cos^2z) \hspace{.33em}\\~\\
=(\cos^2x+\cos^2y+\cos^2z) \hspace{.33em}\\~\\
(1)+(1)+(1)=(\cos^2x+\cos^2y+\cos^2z) \hspace{.33em}\\~\\
\cos^2x+\cos^2y+\cos^2z=3 \hspace{.33em}\\~\\
}\end{align}\)