MEDAL & FAN for correct answer!!! If f(x) varies directly with x2, and f(x) = 96 when x = 4, find the value of f(2). 192 72 32 24
24
can you explain to me how you got that answer?
Okay first, we'll find C For x=4 we have f(x) = 96 so you'll plug that into the equation 96 = C *(4)^2 Can you solve for C?
what does the arrow between the 4 and the 2 mean?
oh wait its an exponet
so c=6
Yes. So you have f(x) = 6x^2 that gets you f(2) f(2) = 6 * (2)^2
ok I GOT IT thanks:):):) , do you mind helping me with another?
What is it?
opps hold on
I only have 10 minutes before I have to leave to my dance class
sorry i got kicked out
lol its okay
Write a quadratic variation equation if g(x) varies directly with x^2, and g(x) = 144 when x = 6. answers: g(x)=24x^2 g(x)=6x^2 g(x)=4x^2 g(x)=1/4x^2
sorry, I have to go, I wasn't able to finish solving the problem, I'm REALLY REALLY SORRY!
its ok
thanks anyway!!! ::))
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