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OpenStudy (anonymous):
MEDAL & FAN for correct answer!!!
If f(x) varies directly with x2, and f(x) = 96 when x = 4, find the value of f(2).
192
72
32
24
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OpenStudy (anonymous):
24
OpenStudy (anonymous):
can you explain to me how you got that answer?
OpenStudy (anonymous):
Okay first, we'll find C
For x=4 we have f(x) = 96 so you'll plug that into the equation
96 = C *(4)^2
Can you solve for C?
OpenStudy (anonymous):
what does the arrow between the 4 and the 2 mean?
OpenStudy (anonymous):
oh wait its an exponet
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OpenStudy (anonymous):
so c=6
OpenStudy (anonymous):
Yes. So you have f(x) = 6x^2 that gets you f(2)
f(2) = 6 * (2)^2
OpenStudy (anonymous):
ok I GOT IT thanks:):):) , do you mind helping me with another?
OpenStudy (anonymous):
What is it?
OpenStudy (anonymous):
opps hold on
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OpenStudy (anonymous):
I only have 10 minutes before I have to leave to my dance class
OpenStudy (anonymous):
sorry i got kicked out
OpenStudy (anonymous):
lol its okay
OpenStudy (anonymous):
Write a quadratic variation equation if g(x) varies directly with x^2, and g(x) = 144 when x = 6.
answers:
g(x)=24x^2
g(x)=6x^2
g(x)=4x^2
g(x)=1/4x^2
OpenStudy (anonymous):
sorry, I have to go, I wasn't able to finish solving the problem, I'm REALLY REALLY SORRY!
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OpenStudy (anonymous):
its ok
OpenStudy (anonymous):
thanks anyway!!! ::))
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