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Mathematics 57 Online
OpenStudy (anonymous):

Every year in Delaware there is a contest where people create cannons and catapults designed to launch pumpkins as far in the air as possible. The equation y = 15 + 110x – 16x2 can be used to represent the height, y, of a launched pumpkin, where x is the time in seconds that the pumpkin has been in the air. What is the maximum height that the pumpkin reaches? How many seconds have passed when the pumpkin hits the ground? (Hint: If the pumpkin hits the ground, its height is 0 feet.)

OpenStudy (anonymous):

The pumpkin's maximum height is 204.06 feet and it hits the ground after 7.01 seconds. The pumpkin's maximum height is 3.44 feet and it hits the ground after 7.01 seconds. The pumpkin's maximum height is 204.06 feet and it hits the ground after 3.44 seconds. The pumpkin's maximum height is 3.44 feet and it hits the ground after 204.06 seconds.

OpenStudy (eyust707):

Lets say the path of the pumpkin looks like this:|dw:1422492369949:dw|

OpenStudy (eyust707):

The point at which the pumpkin will be the highest is right here|dw:1422492440510:dw|

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