Question

4. Consider the relation {(4, 3), (1, 0), (0, 2), (2, 1), (4, 3)}.
(a) Graph the relation.
(b) State the domain of the relation.
(c) State the range of the relation.
(d) Is the relation a function? Explain.

Answer 1

@mathmate i have A and D solved can you help me with B and C?

Answer 2

Is the  supposed to be a negative sign?

Answer 3

Yeah

Answer 4

ok

Answer 5

Sorry bout that

Answer 6

Do you have a sketch for part A, can you draw it, roughly?

Answer 7

What is your answer for part d, and why?

Answer 8

When you have a set of points for a relation, i.e. ordered pairs, the first number is the independent variable, which we usually call x, and the second number is the dependent variable, which we usually call y, or f(x), if the relation is called f as a function of x.
For example,
In (2,3), x=2, y=3.
So far so good?

Answer 9

No i do not a have a sketch for A i can draw one and my answer for D is lol it's very simple but it's a function because there are no duplicate numbers on the y axis

Answer 10

Answer for d is correct, but for the wrong reason! Can you try again?

Answer 11

These ordered pairs (5,2),(6,2),(5,2) still form a function!

Answer 12

Ohhh idk a good explanation then :|

Answer 13

You were close, just review your notes and try again, please...!

Answer 14

But how the only way i know what a function is is by checking to see if the numbers for y match or not

Answer 15

Hey i hate to rush but i need a quick explanation sorry :|

Answer 16

I have written a good explanation for your future questions. If you are looking for short term benefit, I will leave you with what I gave you, the answer is correct for d.

Answer 17

I think you have to rethink why you do these exercises is to help you understand,and understand the next question. Other math topics will depend on the UNDERSTANDING of what you learn today.
I wish you luck!

Answer 18

Oh no i did not mean to drive you away sorry :|

Answer 19

So do you have time to understand how to distinguish a function from non-function?
We were almost there.

Answer 20

Yes i do I'm just busy explain

Answer 21

Close, but not quite.
First off, {(5,2),(6,2)} is a function, even though the y-values repeat.
What really counts is:
when you are given a value of x, you can find a UNIQUE value of y.
For example, {(6,3),(6,4)} is NOT a function because given x=6, we are NOT able to say if y=3 or y=4.
On the other hand, the ordered pairs (4,3),(5,4),(4,3) make a function, because even though the x-values (x=4) repeat, they both give y=3, so no conflicts there.
Do not just base on repetition. The real criterion is
Can you determine y uniquely give a or any value of x.