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Mathematics 20 Online
OpenStudy (anonymous):

Will medal + Fan! http://prntscr.com/5yqoya

Mehek (mehek14):

y is 3 times more than x does this give you an idea of what the answer should be?

OpenStudy (jdoe0001):

\(\bf \begin{array}{cccllll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\ y&={\color{red}{ n}}&x&\implies y={\color{red}{ n}}x \end{array}\\ \quad \\ y=12\qquad x=4\qquad \implies 12={\color{red}{ n}}4\) solve for "n", or the "constant of variation" once you found that, plug it back in the equation

OpenStudy (dtan5457):

y=kx 12=k(4) Solving for k would give you your function.

OpenStudy (dtan5457):

@Agl202 Wow o_O

OpenStudy (anonymous):

thanks

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