Question

i don't understand this sigma question? i have the answer (description) PLEASE HELP SIGMA!!

Answer 1

\[\sum_{4}^{16} t_{k} = 163 and \sum_{4}^{16} u_{k} = -48, evaluate \sum_{4}^{16} (3+2t _{k} -5u _{k})\]

Answer 2

the next step is \[\sum_{4}^{16} 3 + \sum_{4}^{16} 2t _{k} + \sum_{4}^{16} (-5u _{k})\]

Answer 3

but idk why

Answer 4

They used the rule

\[ \Large \sum(x+y) = \sum(x) + \sum(y)\]

Answer 5

where?

Answer 6

Like this

\[\Large \sum_{4}^{16} (3+2t _{k} -5u _{k}) = \sum_{4}^{16}( (3+2t _{k}) + (-5u _{k}))\]

\[\Large \sum_{4}^{16} (3+2t _{k} -5u _{k}) = \sum_{4}^{16}(3+2t _{k}) + \sum_{4}^{16}(-5u _{k})\]

\[\Large \sum_{4}^{16} (3+2t _{k} -5u _{k}) = \sum_{4}^{16}(3)+\sum_{4}^{16}(2t _{k}) + \sum_{4}^{16}(-5u _{k})\]

Answer 7

oh wow, thanks for clearing it up!

Answer 8

you're welcome