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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)). 5 7 9 10
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@leonardo0430
9 perhaps? im not sure >_>
really could use the equation tool, that is why people invented symbols,so you don't have to write "the quantity of 3x minus 1" is this \[f(x)=2x+1\\ g(x)=\frac{3x-1}{2}\]?
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