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Mathematics 22 Online
OpenStudy (anonymous):

@LittleRedRiding

OpenStudy (anonymous):

Which of the following possibilities will form a triangle? Side = 15 cm, side = 7 cm, side = 7 cm Side = 15 cm, side = 7 cm, side = 9 cm Side = 14 cm, side = 6 cm, side = 7 cm Side = 14 cm, side = 6 cm, side = 8 cm

OpenStudy (anonymous):

i got more after that one thxfor helping

OpenStudy (littleredriding):

YIKES!!!! Sorry pal I can't help this has got me scratching my head.

OpenStudy (anonymous):

ok wa about the next one

OpenStudy (anonymous):

What is the area of a triangle that has a height of 6 feet and a base length of 7 feet? 14 feet2 21 feet2 42 feet2 84 feet2

OpenStudy (littleredriding):

42 feet 2

OpenStudy (anonymous):

ok...hay i brb i gtg do suthin so dont leave...but hay my friend just called me and my ringtone for him is hilirous i was crackin up

OpenStudy (littleredriding):

Oh cool brb gotta help some one with Spanish

OpenStudy (anonymous):

ok np

OpenStudy (anonymous):

i brb 2 i gtg do suthin

OpenStudy (anonymous):

@srgntb0$$ I have the answer to your first problem...

OpenStudy (anonymous):

ok i back can u still help srry

OpenStudy (anonymous):

Tina described four triangles as shown below: Triangle A: All sides have length 12 cm. Triangle B: Two sides have length 10 cm, and the included angle measures 60°. Triangle C: Base has length 15 cm, and base angles measure 40°. Triangle D: All angles measure 60°. Which triangle is not a unique triangle

OpenStudy (anonymous):

@IAmInABand420

OpenStudy (anonymous):

@IAmInABand420

OpenStudy (anonymous):

wa is the first one again

OpenStudy (anonymous):

okay, it's not A. That'd be an equilateral. It's not c, that's an acute. Not D either. I'm gonna have to go with B.

OpenStudy (anonymous):

oh my bad that's the wrong one hold on

OpenStudy (anonymous):

is that the first one or the most recent one

OpenStudy (anonymous):

it was the most recent one. the first one I believe will be A

OpenStudy (anonymous):

ok hang on i need help on a few more i gona make a new question and tag u ok

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