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Find the zeros of the equation:
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\[7x ^{2}-144=-x ^{4}\]
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I rewrote the equation so that it has 'x^3' so that it now is in standard form. \[x ^{4}-0x^{3}+7x ^{2}-144=0 \] So now I'm wondering if I need to include the '0x^3' in synthetic division to find the remainder
@Loser66
A. 3, -3, 4i, 0 B. 3, 4i C. 3, -3, 4i, -4i <-----my choice D.-3, -4i
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