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A machine contains 125 gumballs. If the probability of getting a red gumball is 3/5. What is the probability of NOT getting a red gumball? Question 15 options: 5/3 2/5 1/125 75/125
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Let the probability of getting a red gumball be P(R) and let the probability of not getting a red gumball be P(NR). Then we can write: P(R) + P(NR) = 1 ...........(1) Now you need to plug the given value of P(R) into equation (1) and solve for P(NR).
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