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Represent the area of a triangle with a base of 2x + y and a height of 4z (A) 2z(2x+y) (B)2x(z+y) (C)2xyz (D)z(2x + y ) (E) 2z + 4xy
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area of triangle is o.5 *base * height
subsitute the base given adn the height given in to the equation above
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A to E are the choices
\[ A = \frac 12 bh = \frac 12 (2x+y)(4z) = 2z(2x+y) \]
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