Question

PLEASE EXPLAIN, I know the answer.

The expression log3 (8 − x) is defined for all values of x such that
1) x > 8
2) x ≥ 8
3) x < 8
4) x ≤ 8

Answer 1

logarithm is defined only for positive values, so the stuff inside parenthesis must be > 0 :

\[\large 8-x \gt 0\]

solve \(x\)