Question

Solve for x. 3x+4-12=28
@One098

Answer 1

\[3x+4-12=28\]Okay so first, add 12 to both sides.
\[3x+4-12-12=28-12\]The two 12's cancel out, and subtract the two numbers on the right.
\[3x+4=40\]Subtract 4 from both sides.
\[3x+4-4=40-4\]The two 4's cancel out, and subtract the numbers on the right.
\[3x=36\]Divide 3 by both sides.
\[\frac{ 3x }{ 3 }=\frac{ 36 }{ 3 }\]The two 3's on the left cancel out and just divide on the right.
\[x=12\]So x=12.
You can plug it in to check the work.

Answer 2

thank you so much can you help with others

Answer 3

You're most welcome and sure, of course.