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(BEST ANSWER GETS MEDAL!) Find the value of a so that ax^2+24x+16=0 has exactly one rational solution
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Ok so we know that when the discriminant of the quadratic formula equals 0 thenn there is only one solution Using our above equations we have a=a, b=24 and c=16 \[ \text{ Discriminant } = \sqrt{ b^2-4ac}=0\] Now lets plug in our values for b and c and solve for a
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