Question

Will Fan and MEdal!!!!
Express the function y = 2x^2 + 8x + 1 in vertex form.

Answer 1

f(x) = 2x^2 + 8x + 1


Step one: factor out 2

f(x) = 2(x^2 + 4x) + 1


Step two: find perfect square for x^2 + 4x

f(x) = 2(x^2 + 4x + 4) + 1 - (4*2)
= 2(x^2 + 2)^ 2 -7

Therfore, the vertex form is 2(x +2)'^2 -7

vertex (-2, -7)

We hope this helps.


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Academic Gurus Inc.

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