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Mathematics 9 Online
OpenStudy (anonymous):

What is the sum of the geometric series?

OpenStudy (anonymous):

|dw:1422910102500:dw|

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@wrstlr3232

OpenStudy (anonymous):

(A). 10 (B). 21 (C). 21/8 (D). 21/2

OpenStudy (anonymous):

@Luigi0210

OpenStudy (anonymous):

@ParthKohli

OpenStudy (mathmath333):

\(\large \begin{align} \color{black}{\sum_{i=1}^{3} 8\times \left(\frac{1}{4}\right) ^{(i-1)} \hspace{.33em}\\~\\ =8\times \left(\frac{1}{4}\right) ^{(1-1)}+8\times \left(\frac{1}{4}\right) ^{(2-1)}+8\times \left(\frac{1}{4}\right) ^{(3-1)} \hspace{.33em}\\~\\ }\end{align}\)

OpenStudy (anonymous):

do I actually minus those exponets together first ex. (1-1)(2-1)(3-1).

OpenStudy (mathmath333):

\(\large \begin{align} \color{black}{\normalsize \text{u should proceed like this} \hspace{.33em}\\~\\ =8\times \left(\frac{1}{4}\right) ^{(1-1)}+8\times \left(\frac{1}{4}\right) ^{(2-1)}+8\times \left(\frac{1}{4}\right) ^{(3-1)} \hspace{.33em}\\~\\ =8\times \left(\frac{1}{4}\right) ^{(0)}+8\times \left(\frac{1}{4}\right) ^{(1)}+8\times \left(\frac{1}{4}\right) ^{(2)} \hspace{.33em}\\~\\ }\end{align}\)

OpenStudy (anonymous):

(A). 10

OpenStudy (anonymous):

Well I got 10.5, but there is no 11 so I went with A.

OpenStudy (anonymous):

Nevermind its (D). opps(:

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