You could walk across the Lehigh River if you had a pair of water-walking boots shaped like canoes. If each boot is 25cm high and 35cm wide how long must they be to support a 75kg person? I can't figure it out :(
In order to support a 75 kg person, 75 kg of water must be displaced by the boots. Can you figure out what volume of water has a mass of 75 kg? You need to know the density of water.
the density is 1000
Right, 1000 kg/m^3. So how many m^3 would have a mass of 75 kg?
uhm idk..
Density of a substance is calculated using\[D=\frac{ m }{ V }\]You know the density (1000 kg/m^3) and the mass (75 kg). Are you able to rearrange the equation and solve for volume?
so mass x density
To get V out of the denominator, multiply both sides by V, giving\[DV=m\]Then to isolate V, divide both sides by D, giving\[V=\frac{ m }{ D }\]Noe calculate V
uhm 0.75?
Not quite. To divide a number by 1000, move the decimal three places to the left. Or use a calculator.
oh it's .075
sorry . that was a typo
Correct. So the total volume of both boots must be 0.075 m^3. So what must be the volume of one boot?
uhm would i divide by 2?
Exactly
ok so 0.0375
Perfect, the volume of one boot must be 0.0375 m^3. Assume the boot is shaped like a big shoe box (i.e. a rectangular prism). Do you know how to calculate the volume of a rectangular prism?
l x w x h
Exactly. So the question gives h and w, and you know what the volume has to be. Can you rearrange\[V=l \times w \times h\]and solve for l? Don't forget that the dimensions of the boot must be in meters in order for the volume to be in m^3.
l=v/w(h)
Perfect. Plug in the values and solve.
ok so i got 0.0525
Not what I get. Try again.\[l=\frac{ V }{ w \times h } = \frac{ 0.0375 }{ \left( 0.25 \right) \left( 0.35 \right) } = ?\]
oh its 0.43
Tada. Well done. Now to answer the question. How long do the boots have to be?
uhm wait i thought that was how long they needed to be because that's the length.
Sorry, I didn't mean to confuse you. You have indeed figured out how long they have to be. Your answer is in meters. The other dimensions are given in cm. It might be a good idea to answer in cm.
so 43cm
Good work!
thank u ! :) i appreciate it
You're welcome.
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