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Can I have some help with this one problem? 2x/3x^3 = ?
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\(\bf \cfrac{2x}{3x^3}\implies \cfrac{2\cancel{ x}}{3xx\cancel{ x}}\implies ?\)
\[\frac{ 2x }{ 3x^3 }\]The numbers are already in lowest terms so you can't do any more with them. But can you simplify the x/x^3 part?
Oh, now I think I get it. It's 2/3 x^2 ?
Correct
Thanks!!!
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