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Please explain how to do it as well as result: The sum of two non-negative numbers is 20. Find the numbers If the sum of their squares is as large as possible; as small as possible. This is optimization.
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if the sum is \(20\) and one is say \(x\) then the other is \(20-x\) maximize \[f(x)=x^2+(20-x)^2\]
not sure what you are supposed to use, but \[f(x)=2 x^2-40 x+400\] is a quadratic, min is at the vertex
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