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first order lnear diff eq
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\[\large \frac{\sin 2\theta}{2} \ne \sin \theta \]
ah yes i forgot.
looks good, put it in standard form and do the regular stuff
dp/dtheta+ p costheta= sin2theta/2
\[\large p' + (\cos\theta)p = \frac{\sin (2\theta)}{2}\]
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\(IF = e^{\int \cos\theta d\theta}\)
e^sintheta
yes keep going :)
i take out 1/2 from the right side
yes
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write \(\sin(2\theta)\) as \(2\sin\theta \cos\theta\) and substitue \(u = \sin\theta\)
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