Question

Find x in the following applying pythagoras theorem:

The right angle triangle is in a semi-circle. The hypotenuse/diameter is 10cm wide. The shorter side of the triangle is simply x and the remaining side is 2x. What is x?

Answer 1

\[\sqrt{20}\]

Answer 2

\[(x)^{2} + (2x)^{2} = x^{2} + 4x^{2} = 5x^{2} \]

Answer 3

acc to Pythagoras theorem

Answer 4

the above result equals \[10^{2}\]

Answer 5

hope you can solve further!