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Could someone help me with this please? Variable y varies directly with x2, and y = 72 when x = 6. Enter the constant of variation for the quadratic variation equation. y = ? x2 I think the answer is 2 but I'm not very sure
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y = kx^2 where k is the constant of variation if you plug in x = 6 and y = 72 into the above you can calculate k;- 72 = k * (6)^2
so 36k = 72 now divide both sides by 36
so what is the value of k?
72/36 would be 2 so would k = 2?
I agree with you @--Irwin
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