Question

find the value(s) of guaranteed by the
Mean Value Theorem for Integrals for the function over the
given interval.
F(x)=9/x^3 [1,3]

Answer 1

\[f(c)=\frac{9}{c^3}=\frac{1}{3-1}\int_1^3\frac{9}{x^3}\,dx\]
\[c^3=\frac{2}{\displaystyle\int_1^3\frac{dx}{x^3}}\]