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Help Please?! 10a^3 b - 12a^2 b^2
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does this need to be simplified?
I think so
@alekos
well you just need to find the common factors for each term One of these is 2. what do you think the other two are?
Would it be 2a (a-b) 6ab (a-b)
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nice try but no. the other two factors are a^2 and b so just go like this 2(a^2)*b(ma - nb) I'll let you find m and n
Okay so m would be 5a & n would be 6b, right?
yep. that's it m=5 n=6
So then it would be 2(a^2) b(5a-6b) @alekos
yes. you got it!
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Yay! Can u help me on another one?
yeah sure
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anyone know how to explain this so its easier for me to understand? b(1)=2, b(n)=
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