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Biology 25 Online
OpenStudy (anonymous):

Based on Chargaff’s rule, the percentage of cytosine in the DNA of the bacterium S. Lutea in Figure 12–3, should be around A. 26.6% ************************ B. 73.2% C. 36.6% D. 29.4%

OpenStudy (anonymous):

OpenStudy (anonymous):

can someoone check my answer :) @e.mccormick @VectorPrime @NaomiBell1997 @love10129151 @akonkel @dtan5457 @hhelpplzzzz @Kainui @MCLover1477 @basketball3000 @alana242

OpenStudy (anonymous):

Welcome to Open Study!

OpenStudy (anonymous):

What do u think it is?

OpenStudy (anonymous):

well i think its A

OpenStudy (anonymous):

this might help http://www.flashcardmachine.com/biology-finalexamreview.html

OpenStudy (anonymous):

based on that its 36.6%

OpenStudy (anonymous):

Hope I helped:)

OpenStudy (anonymous):

oh i see how it is 36.6% thanks :)

OpenStudy (anonymous):

np:)

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