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Please help! Medal and fan! The length of one leg of a right triangle is (x - 6) centimeters, and the area is [(1/2)(x^2) - 7x + 24] square centimeters. What is the length of the other leg? I'm pretty sure that the equation i need to solve is [(1/2)(x^2) - 7x + 24) = [(1/2) (x - 6) (h) but I just dont know where to start solving it
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@dtan5457 @Loser66
|dw:1423017179963:dw|
solve for b or h
Let's call the other leg "y" so (x-6) * y =[(1/2)(x^2) - 7x + 24] y = [(1/2)(x^2) - 7x + 24] / (x-6)
1/2*(x^2-7x+24)=1/2bh x^2-7x+24=b(x-6) b=(x2-7x+24)/(x-6)
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