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Chemistry 19 Online
OpenStudy (anonymous):

Grams of butane you used “X” grams of butane mL of butane corrected to STP = 22,400 mL 0.2 g butane = x . 50 mL 22,400 L 4480 = 44x 101.8 g butane = x

OpenStudy (anonymous):

@DanJS

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