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Mathematics 9 Online
OpenStudy (anonymous):

What is the period, in seconds, of a simple pendulum of length 3 meters? Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places.

OpenStudy (perl):

do you know the equation for the period of a pendulum

OpenStudy (perl):

I think it involves a square root

OpenStudy (anonymous):

t= 2pi sqrt(L/g)

OpenStudy (perl):

ok you are given L = 3, and g = 9.8 , so plug those in

OpenStudy (anonymous):

3.48?

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