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solve the equation. x^3 - 1=0. i know it means find the third roots of 1. I have an answer but im not sure if its right. I got 3
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This is powers and roots of complex numbers
\(\large\color{slate}{ a^3-b^3=(a-b)(a^2+ab+b^2) }\)
use that here: \(\large\color{slate}{ x^3-1^3=~..... }\)
we have to use DeMoivre's Theorem
I am out.... (why ?)
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idk, thats how we do it
for ex: [32(cos(2pi) + isin(2pi)]^1/5
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