What is the sum of the first 18 terms of the arithmetic series 11 + 15 + 19 + 23 + ...? A) 684 B) 810 C) 831 D) 846 If anyone could help, that'd be really appreciated. Please include step by step intructions. Thank you
Well each number increases by 4, so keep adding 4, until you reach an 18th number, then add them all together.
use the formula Sn = n(a1+an)/2
I tried that and didn't get anywhere close to the answers provided. I must've done something wrong or something and how would I use the formula?
\[11+15+19+23+27+31+35+39+43+47+51+55+59+63+67+71+75+79\]
The last number is 79.
Put all those numbers into a calculator.
AHHH, I got it now. Thank you, I must've been doing something wrong since I got a bigger number but now I got it. I appreciate it, thank you once again
You're welcome!!
you also use the formula an= a1 + (n-1)d, in order to find an then use the first formula i gave you Sn is what your finding(the sum) n=# of terms(18) a1= first term, an=nth term
one098's way is too long
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thnx @One098
did this help?
Yes thank you! That's a much simpler way and it was step by step so I understood it well. Thank you!
yw cx
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