medal
If f(x) = 2x - 4, and g(x) = (x^2 + x + 5), find g (f(x))
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OpenStudy (babyslapmafro):
Replace any "x" in the function g(x) with f(x)
OpenStudy (babyslapmafro):
for example:
OpenStudy (babyslapmafro):
if f(x) = x+2 and g(x) = x^2+4
g(f(x))= (x+2)^2 + 4
OpenStudy (anonymous):
x) = x+2 and g(x) = x^2+4
g(f(x))= (x+2)^2 + 4
@Babyslapmafro this is the right equation.
OpenStudy (babyslapmafro):
@aballer101
is that clear?
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OpenStudy (anonymous):
g (f(x)) = g(2x-4) (substituted f(x)=2x-4 )
g(x) = (x^2 + x + 5)
g(2x-4) means instead of x we have to substitute 2x-4 in g(x)
g(2x-4)=(2x-4)^2+(2x-4)+5
OpenStudy (babyslapmafro):
correct
OpenStudy (anonymous):
a=-2x and b=4
OpenStudy (anonymous):
g(2x-4)=(2x-4)^2+(2x-4)+5
OpenStudy (babyslapmafro):
now just simplify that equation
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OpenStudy (anonymous):
thank you g=fpor the report
OpenStudy (anonymous):
Your Welcome :)
OpenStudy (anonymous):
u did it ? @TypnoEchosis
OpenStudy (anonymous):
Indeed I did.
OpenStudy (anonymous):
2gx-4g-4x2+14x-17 = 0 is that right?
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OpenStudy (anonymous):
why is that? cant have some fun?
OpenStudy (babyslapmafro):
simplify this part of the equation:
(2x-4)^2+(2x-4)+5
OpenStudy (anonymous):
4x2 - 14x + 17
OpenStudy (anonymous):
I am sorry and it wont happen again but there was no need to report me
OpenStudy (anonymous):
@grrrxxiii i didnt report u
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OpenStudy (anonymous):
i know it was the @TypnoEchosis
OpenStudy (babyslapmafro):
expand (2x-4)^2 first:
(2x-4)^2 = 4x^2 - 16x + 16
OpenStudy (babyslapmafro):
yes, you have the correct final answer:
4x2 - 14x + 17
OpenStudy (anonymous):
thats it.. i dont have to simplify 4x2 - 14x + 17 ?
OpenStudy (babyslapmafro):
i would leave it in this form.
a quadratic equation.
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