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Find all digits x and y such that 6xx(bar on top) − 1y8(bar on top) = 47y(bar on top). (As usual, 6xx(bar on top) is the 3-digit number with 6 in the hundreds place, x in the tens place, and x in the ones place, etc.)
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\[6xx - 1y8 = 47y\]
expand it and see if you can get an useful relation between x and y
\[(600+10x+x) - (100+10y+8) = (400+70+y)\] simplify
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