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Mathematics 19 Online
OpenStudy (kj4uts):

Solve on interval [0, 2pi): (cos x+1) (2cos^2 x-3 cos x-2) =0 I think B. x=pi, x=2pi/3 and x=4pi/3 is the answer is this correct. Thank you!

OpenStudy (kj4uts):

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