Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a + 3.75b = 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?
Plug in '82' for 'b' in the equation, and solve for 'a': \(10.50a + 3.75b = 2071.50\) \(10.50a + 3.75(82) = 2071.50\) Multiply: \(10.50a + 307.50 = 2071.50\) Sub tract 307.5 to both sides, what's 2071.50 - 307.50? @Rafyy
1764 lol @iGreen.
Yes, so we have: \(10.50a = 1764\) Now divide 10.50 to both sides, what's 1764 / 10.50?
i got 168.
Yes, so 168 adult tickets were sold.
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