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Mathematics 16 Online
OpenStudy (anonymous):

What was the hiker's average velocity during part C of the hike? A. 4.0 km/h south B. 6 km/h west C. 0.10 km/h north D. 10 km/h south west http://static.k12.com/calms_media/media/1357500_1358000/1357619/1/c08f9b06e1a4a6a86101eef8f4952090ef8fd57c/MS_PHYS_SCI_286558.jpg

OpenStudy (anonymous):

I think B

OpenStudy (anonymous):

@iGreen.

OpenStudy (anonymous):

Velocity is Distance divided by Time

OpenStudy (anonymous):

so add all the distance up and then divide by what?

OpenStudy (anonymous):

You divide distance by time.

OpenStudy (anonymous):

so it would be 6+4+6+8=24 then 24/4?

OpenStudy (anonymous):

For the first one it says 6km and the start time was 8, and the end time is 9.

OpenStudy (anonymous):

So that's 6 / 1 or 6.

OpenStudy (anonymous):

so i am correct?

OpenStudy (anonymous):

2nd one is 4km and time is 9:00-9:45, which is 45 minutes, or 0.75 hours. 4/0.75 = 5.33

OpenStudy (anonymous):

so i am correct or no?

OpenStudy (anonymous):

Um..I'm not sure

OpenStudy (anonymous):

Ok Thanks ^_^

OpenStudy (anonymous):

xD

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