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If (x + yi) + 6i = 2, what is x + yi?
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2-6i I think
See, in case of complex numbers, real part is equal to real part and imaginary part is equal to imaginary part..
\(x + iy + 6i = 2\)
The term without i is real and the term with i are imaginary..
Real on left side is \(x\) and real on right side is 2..
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So, \(x=2\)..
On left side, imaginary part is : 6i + yi, and on right, there is no imaginary part, or you can say it is 0..
\(yi + 6i = 0 \\ (y+6)i = 0 \\ y = -6\)
Therefore, you know x and y values now.. \(x+iy = 2 + i(-6) \\ x + i y = 2 - 6i\)
Thank you @waterineyes
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