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Mathematics 12 Online
OpenStudy (poetryprincess):

Anyone willing to help? Please? I'll give fan and medal.

OpenStudy (poetryprincess):

OpenStudy (anonymous):

do you know what OR is equal to

OpenStudy (anonymous):

looks like \(2(OR)=NP\) right? so solve \[2(3x-4)=5x+20\] in a few steps

OpenStudy (poetryprincess):

How do I solve that? @satellite73

OpenStudy (anonymous):

6x - 8 = 5x + 20 Multiply 2 with the numbers in parenthesis

OpenStudy (anonymous):

then subtract \(5x\) from both sides, get \[x-8=20\]

OpenStudy (anonymous):

Yep!

OpenStudy (anonymous):

Thank you for the medal! My first.

OpenStudy (anonymous):

now add 8 to get x = 28

OpenStudy (poetryprincess):

Ahhh, I believe I got it now, thanks both of you. =)

OpenStudy (anonymous):

Np

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