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Mathematics
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@mathmath333
$$ \text{area_of_rectangle} = (\sqrt[5]{16}) \cdot 2^\frac{1}{5} = \bigg(\sqrt[5]{2^4}\bigg) \cdot \sqrt[5]{2} = \\ = \big(\sqrt[5]{2}\big)^4 \cdot \sqrt[5]{2} = (\sqrt[5]{2})^5 = 2 $$
@pitamar could you help with one more?!?!?!?
sure
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Ok. Well we have: $$ \bigg(5^\frac{3}{4}\bigg)^\frac{2}{3} $$ We can say $$ \bigg(5^\frac{3}{4}\bigg)^\frac{2}{3} = \large5^{\big(\frac{3}{4} \cdot \frac{2}{3}\big)} = 5^{\frac{2}{4}} = 5^\frac{1}{2} = \sqrt{5} $$
thank so very very much!!!!!!!!!!!!!!!
Sure np
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