Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the rate of 2 cm3/min. At what rate is the depth of the water changing at the instant when the water in the tank is 8 cm deep? Show all work and include units in your answer. Give an exact answer showing all work and include units in your ans

Question

anonymous · Answer

@jim_thompson5910  :) plz help!!

jim_thompson5910 · Answer

do you have a drawing set up?

anonymous · Answer

no not for this one

jim_thompson5910 · Answer

what does the cross section of the cone look like? what shape?

anonymous · Answer

can you draw it out please i have a limited time for this :(

jim_thompson5910 · Answer

I can't help with tests. Sorry.

anonymous · Answer

it's not an exam im doing hw :( and im at the library! I only have 20 minutes left

jim_thompson5910 · Answer

are you able to come back? It's not good to be rushed like this

jim_thompson5910 · Answer

Especially since you have other problems to work on

jim_thompson5910 · Answer

anyways, the drawing looks like this 

|dw:1423446620435:dw|

jim_thompson5910 · Answer

the ultimate goal is to find the rate of change in the height of water when it's 8 ft deep

|dw:1423446715083:dw|