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Biology 13 Online
OpenStudy (anonymous):

Consider the following cross: Parent 1: YyTt Parent 2: YyTt Using the rules of probability, determine the probability that the offspring will show YyTT genotype? 1 8 1 16 1 2

OpenStudy (anonymous):

@Compassionate

OpenStudy (anonymous):

@Abhisar

OpenStudy (anonymous):

@Science_ALLY

OpenStudy (shrutipande9):

do u know how to do a punnet square?

OpenStudy (anonymous):

@whydoihavetosignup1

OpenStudy (anonymous):

nope

OpenStudy (shrutipande9):

do u know how to make gametes from the given genotype?

OpenStudy (anonymous):

no i have no idea so far alot of people dont get it either

OpenStudy (abhisar):

Me too don't get it ;(

OpenStudy (abhisar):

Come on let's see how to do it together :D

OpenStudy (anonymous):

ok lol

OpenStudy (anonymous):

@shrutipande9

OpenStudy (abhisar):

Parent 1 = YyTt Parent 2 = YyTt Now we will have to make a punnet square and perform a cross between these two.

OpenStudy (abhisar):

|dw:1423456899167:dw|

OpenStudy (abhisar):

Can you fill in the above punnet square?

OpenStudy (anonymous):

|dw:1423457089538:dw|

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