Question

dx/dt=x(a^2-x^2). There's two variables! ugh if x is a dependent variable and a is a varying parameter, how am I going to graph it on the x and y axis?

Answer 1

@dan815

Answer 2

0=x(a+x)(a-x) /
I know that equilibrium is at x = 0,-a, a

Answer 3

oh wait I think I answered my own question -_-!