Question

Variable y varies directly with x2, and y = 96 when x = 4.

What is the value of y when x = 2?

y =

Answer 1

y=kx^2

Answer 2

\[y \; \; \; \alpha \; \; \; x^2\]

Answer 3

96=kx^2

Answer 4

So let the constant of proportionality is k..
\( y = kx^2\)

Answer 5

96=k(4)^2

Answer 6

96=k(16)

Answer 7

k=6

Answer 8

k=6?

Answer 9

y=6x^2

Answer 10

what does that simplify to

Answer 11

thanks i was confused can you help in about 30-60 seconds

Answer 12

y=6(2)^2

Answer 13

y=6*4

Answer 14

y=24

Answer 15

So the answer to your problem is that when x = 2, y equals 24.

Answer 16

Hope this helps you to understand the problem.