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Help! Which of the following equations describes the graph? a. y=3x^2+4 b. y=-3x^2-4 c. y=-3x^2+4 d. y=3x^2-4
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it opens down, so the leading coefficient is negative that rules out A and D
what do you see on the graph where \(x=0\) i.e where does the graph cross the y axis?
Ok i think the answer is c because the y axis is positive 4 and since its going downwards it is going to be a negative which is -3x
@satellite73
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yes, exactly it is almost always C anyways
ok so the answer is c
yup
thank you
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