Question

Urgent *will medal*: How many ways can a person choose a three-digit area code if the first number cannot be 0, 1, or 8, and no digit can repeat?

Thanks c:

Answer 1

HI!!

Answer 2

i think we can do this
you have 7 choices for the first number
then 9 for the second (since one is used up) and 8 for the third
try
\[7\times 9\times 8\]