Question

How do I solve this?

Answer 1

what is the formula to find out the solution of a quadratic?

Answer 2

I don't remember. That's the problem.

Answer 3

\(x= \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 4

To have 2 real roots, \(\sqrt{b^2-4ac} >0 \), in your problem, replace b = -3 and solve for c