Question

How many grams of magnesium metal will react completely with 6.3 liters of 4.5 M HCl? Show all of the work needed to solve this problem.

Mg (s) + 2 HCl (aq)yields MgCl2 (aq) + H2 (g)

Answer 1

you need to find the moles present of HCl.

Use: \(molarity=\dfrac{moles}{L_{solution}}\)

Next relate the moles and stoichiometric coefficients to find the moles of Mg

\(\sf \dfrac{moles~of~Mg}{Mg's~coefficient}=\dfrac{moles~of~HCl}{HCl's~coefficient}\)

next convert moles of Mg to mass

\(moles=\dfrac{moles}{Molar~mass}\)