If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2(x - pi divided by three), what should be used for Xmin and Xmax? Explain your answer.
@satellite73
the equation is y=5+3 cos2 (x-(pi/3))
@.Sam.
@campbell_st
Is \(y=5+3\cos\left(2x-\frac{2\pi}{3}\right)\)?
\[y=5+3\cos 2(x-\frac{ \pi }{ 3 })\]
thats better
of course it is the same thing that @thomas5267 wrote
i suppose you'll have to find the domain first right?
this is two questions right ?
it's asking for Xmax and Xmin and you'll need to explain
one is two periods where you have pretty much an infinite number of choices, since that is what preiodic means
Xmax is not a math term i am familiar with
ooh i see !!
i think it means x maxima
it wants the left and right hand endpoints is all
and how do you solve for that?
the easiest way for me would be to do this the period of cosine is \(2\pi\) so two periods would have length \(4\pi\)
yup i get that part
but how do i find the smallest possible domain?
set \[2x-\frac{2\pi}{3}=0\] solve for \(x\) then set \[2x-\frac{2\pi}{3}=4\pi\] and solve that for x
ok hold up
would x be \[\frac{ 2\pi }{ 6 }\] ?
i would write \(\frac{\pi}{3}\) but yes
so \[4\pi\] is equal to 0
what does \(4\pi=0\) mean?
oops. nvm i misread something
and the other one would be \[\frac{ 7p }{ 3 }\]
would that be the start point and the end point?
that is one way
but look, cosine is periodic
you want two periods you can start and end anywhere \(4\pi\) units apart
I would add a random multiples of pi to both the start point and end point just to annoy the teacher lol.
but they're asking for the smallest domain which is why we started at 0 right?
i guess i cannot get my point across you can start at 0 and went to \(4\pi\) because it is easy but you could go from \(-2\pi\) to \(2\pi\) instead
for that matter you could go from \(-e^2\) to \(-e^2+4\pi\) it really makes no difference
yea i get that
then what do they mean by using the smallest domain, because that the part where it keeps throwing me off
that is what we did
they said interval of 4 pi and we did it
I guess smallest means xmax-xmin is the smallest?
oh ok, i think i get it now. thank you guys! :)
this helped a lot
yw
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