Algebra
10 Online
OpenStudy (anonymous):
Solve the inequality 5(2x + 1) < 10.
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Nnesha (nnesha):
\(\huge\color{Green}{{\rm welcome}\rm~to~open~study!!!!}\) \(\Huge \color{blue}{\star^{ \star^{\star:)}}}\Huge \color{red}{\star^{ \star^{\star:)}}}\)
\(\Huge \color{orange}{\star^{ \star^{\star:)}}}\Huge \color{purple}{\star^{ \star^{\star:)}}}\)
Nnesha (nnesha):
divide by 5 both side
Nnesha: then subtract 1 both side
Nnesha: then again divide by 2 both side
Nnesha: then u are done :)
Nnesha (nnesha):
let me know what you get ?? :)
Nnesha (nnesha):
if you divide or multiply by negative sign then you have to flip the sign
Nnesha (nnesha):
@tatyanna1402 ^^^
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OpenStudy (anonymous):
ok thanks
Nnesha (nnesha):
what you got ?
OpenStudy (anonymous):
yeah, thank you
now what about
5x < 16 + x
Nnesha (nnesha):
FOR THIS one you have to move x on left side then combine like terms
OpenStudy (anonymous):
so subtract x?
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Nnesha (nnesha):
yes right
OpenStudy (anonymous):
and get 4x<16
Nnesha (nnesha):
yes now divide both side by 4
OpenStudy (anonymous):
exactly(:
Nnesha (nnesha):
yeah
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OpenStudy (anonymous):
i got x<4
Nnesha (nnesha):
yeah _^
OpenStudy (anonymous):
i got a question..
Nnesha (nnesha):
what ??
OpenStudy (anonymous):
13x - 4 < 12x - 1
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Nnesha (nnesha):
okay u need all x;s on one side and number without variable other side
Nnesha (nnesha):
first subtract 12x both side
OpenStudy (ribhu):
x<1/2
Nnesha (nnesha):
o_O
Nnesha (nnesha):
:)
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OpenStudy (anonymous):
1x-4<-1
Nnesha (nnesha):
yes right
Nnesha (nnesha):
now add 4 both side
OpenStudy (anonymous):
1x<-3
Nnesha (nnesha):
|dw:1423568612024:dw|u have to add 4 both side
so right side you have 4-1 which is equal to ??