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Physics 9 Online
OpenStudy (anonymous):

A ball is thrown directly downward with an initial speed of 8.50 m/s, from a height of 29.4 m. After what time interval does it strike the ground?

OpenStudy (anonymous):

I would use the equation:\[y = y_{0}+v_{0}t+\frac{1}{2}gt^{2}\] y0 = 29.4 m y = 0 m g = 9.8 m/s^2 vo = 8.5 m/s

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