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Given the equation of the parabola -36y=x^2 The focus of the parabola is: (0, 9) (-9, 0) (0, -9)
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@Directrix
Let's try this. Go here and enter this: Focus -36y=x^2 Then, let it compute and look for the table and read from the table what the Focus is.
ok
were do i enter it?
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What did you get
(0, -9)
That is also what I got.
ok i will put a new question out i have another one
ok
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actually i figured it out! thanks
Okay, that's good.
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